Modern Chemistry, Lesson 27: Determination of Molecular Weights of Liquids and Solids

Duration: 30 min

Creator: Encyclopaedia Britannica Educational Corporation

Description: A known weight of a liquid is evaporated in such a way that the vapor formed displaces a corresponding volume of air. The volume of this air, its temperature and pressure are measured. Shows that the volume of displaced air equals the volume of the weighed sample of the unknown as a gas under the same conditions.

Metadata Source:Catalog of Classroom Teaching Films for Georgia Schools, No. 10 (Georgia Department of Education)